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Blog Support for Growing Mathematicians

Archive for February, 2011

Don’t Stress over Sneaky Advertising


The Sneaky Advert exercise is to get you thinking mathematically about some of the tricks that can be used by advertisers to trick you into thinking that there are some  great bargains to be had in the stores. Of course, sometimes there are. Other times, the sneaky adverts are to get customers in the door. […]

Welcome to H3 Maths!


We are moving on to Ratios next. My Dad (who was a keen maths student) taught me a cool way to use ratios and this secret will be shared at class next week! Also, I now have your logons for MathsOnline, so there is plenty of work heading your way 🙂

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10 x 9 x 8 + (7 + 6) x 5 x 4 x (3 + 2) x 1 = 2020

NCEA Level 2 Algebra Problem. Using the information given, the shaded area = 9, that is:
y(y-8) = 9 –> y.y – 8y – 9 =0
–> (y-9)(y+1) = 0, therefore y = 9 (can’t have a distance of – 1 for the other solution for y)
Using the top and bottom of the rectangle,
x = (y-8)(y+2) = (9-8)(9+2) = 11
but, the left side = (x-4) = 11-4 = 7, but rhs = y+? = 9+?, which is greater than the value of the opp. side??
[I think that the left had side was a mistake and should have read (x+4)?]

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