Welcome to H3 Maths

Blog Support for Growing Mathematicians

Welcome to H3 Maths!

February14

We are moving on to Ratios next. My Dad (who was a keen maths student) taught me a cool way to use ratios and this secret will be shared at class next week! Also, I now have your logons for MathsOnline, so there is plenty of work heading your way 🙂

by posted under Uncategorized | 4 Comments »    
4 Comments to

“Welcome to H3 Maths!”

  1. March 2nd, 2011 at 4:55 pm       Alina Jacob Says:

    Mr Hayden
    for maths online do we have to do all the tasks or just week 6.
    Thanks
    Alina


    • March 8th, 2011 at 11:48 am       h3maths Says:

      Thanks Alina. Just the Week 6 ones, but please feel free to go on to the next ones if you have time.


  2. February 21st, 2011 at 3:55 pm       millicent hargrave Says:

    hey mr hayden…..

    just wondering when will we be getting our 1st assingment ?
    and also do we have any homework?

    thanks
    from millicent hargrave
    9.3/9c maths bcc 2011


    • February 25th, 2011 at 12:48 am       h3maths Says:

      Hi and thanks for your questions. The first assignment is on March 15 (numbers, etc. from Chapter 1 and 2 in the text). Yes, there is homework after most lessons! Very rarely do I not give homework as it helps revise important concepts used in class and reinforce your understanding of a topic. Can you imagine concrete without reinforcing? It would turn to powder! The same applies to our learning – we need to reinforce by going over what we have done in class and apply our learning to new situations. This way we get good exercise for our brains too!


Post Support

The graph on the left (Coronavirus) is for a time period of 30 days, while the one on the right (SARS) is for 8 months! Very poor graphical comparison and hardly relevant, unless it is attempting to downplay the seriousness of the coronavirus?

10 x 9 x 8 + (7 + 6) x 5 x 4 x (3 + 2) x 1 = 2020

NCEA Level 2 Algebra Problem. Using the information given, the shaded area = 9, that is:
y(y-8) = 9 –> y.y – 8y – 9 =0
–> (y-9)(y+1) = 0, therefore y = 9 (can’t have a distance of – 1 for the other solution for y)
Using the top and bottom of the rectangle,
x = (y-8)(y+2) = (9-8)(9+2) = 11
but, the left side = (x-4) = 11-4 = 7, but rhs = y+? = 9+?, which is greater than the value of the opp. side??
[I think that the left had side was a mistake and should have read (x+4)?]

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