## Welcome to H3 Maths

Blog Support for Growing Mathematicians

### Pi Day, Oz Style

March14

Yes, we were ahead of our lagging mathematicians in other classrooms today – with an early Pi DAY.

March 14 (3.14) is a day ahead of our American counterparts and staff were delighted to receive small jam and lemon tarts to celebrate this auspicious day in the Mathematics calendar! Would love to see photos from other Pi Day celebrations!! We were going to post ours but the vultures descended very quickly and all were gone before we could say Pi to 100 decimal places!! (we can get around this problem with a bigger Pi next year)

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#### Post Support

10 x 9 x 8 + (7 + 6) x 5 x 4 x (3 + 2) x 1 = 2020

NCEA Level 2 Algebra Problem. Using the information given, the shaded area = 9, that is:
y(y-8) = 9 –> y.y – 8y – 9 =0
–> (y-9)(y+1) = 0, therefore y = 9 (can’t have a distance of – 1 for the other solution for y)
Using the top and bottom of the rectangle,
x = (y-8)(y+2) = (9-8)(9+2) = 11
but, the left side = (x-4) = 11-4 = 7, but rhs = y+? = 9+?, which is greater than the value of the opp. side??
[I think that the left had side was a mistake and should have read (x+4)?]