## Welcome to H3 Maths

Blog Support for Growing Mathematicians

### Gradients of Straight Lines revisited

July23

You are probably already familiar with the concept that the gradient or slope of a straight line is how much it rises over a given horizontal length – that is, the rise divided by the run. This video clip from Waldomaths is a very good explanation of gradients, and uses several examples:
The gradient of a straight line can also be found using the equation of the given line. Check here for more details.

by posted under Uncategorized | Comments Off on Gradients of Straight Lines revisited

#### Post Support

10 x 9 x 8 + (7 + 6) x 5 x 4 x (3 + 2) x 1 = 2020

NCEA Level 2 Algebra Problem. Using the information given, the shaded area = 9, that is:
y(y-8) = 9 –> y.y – 8y – 9 =0
–> (y-9)(y+1) = 0, therefore y = 9 (can’t have a distance of – 1 for the other solution for y)
Using the top and bottom of the rectangle,
x = (y-8)(y+2) = (9-8)(9+2) = 11
but, the left side = (x-4) = 11-4 = 7, but rhs = y+? = 9+?, which is greater than the value of the opp. side??
[I think that the left had side was a mistake and should have read (x+4)?]