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How can someone born in 2020 be older than someone born in 2019?

January4

Solution: If someone is born, say, at 1am in the morning of January 1 2020 in Sydney, then everyone born in the UK in the afternoon of December 31 2019 will be younger than them but born the previous year.

In fact, the number of people born in 2020 who are older than someone born in 2019 is going to be in six figures. About 360,000 people are born every day. (Most in Asia). A child born in French Polynesia between 10pm-midnight on Dec 31 2019 will be younger than all the Jan 1 2020 births until that moment, i.e until 6pm in Beijing, 3.30pm in Delhi, and so on. A fair estimate is probably about half of 360,000.

(Hat tip to the reader who said that anyone born in 2020BC will be older than anyone born in 2019AD)

source and more puzzles such as the one below are from The Guardian

Second Puzzle: Fill in the blanks in the following ‘countdown’ equation so it makes arithmetical sense:

10 9 8 7 6 5 4 3 2 1 = 2020

[One answer in Post Support]

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NCEA Level 2 Algebra Problem. Using the information given, the shaded area = 9, that is:
y(y-8) = 9 –> y.y – 8y – 9 =0
–> (y-9)(y+1) = 0, therefore y = 9 (can’t have a distance of – 1 for the other solution for y)
Using the top and bottom of the rectangle,
x = (y-8)(y+2) = (9-8)(9+2) = 11
but, the left side = (x-4) = 11-4 = 7, but rhs = y+? = 9+?, which is greater than the value of the opp. side??
[I think that the left had side was a mistake and should have read (x+4)?]

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