## Welcome to H3 Maths

Blog Support for Growing Mathematicians

## Posts tagged with algebra

### Solving simple Linear Equations

July4

This site offers some good, graded exercises to solve for variables, along with solutions. Other revision topics are also available: LINEAR EQUATIONS – Solve for x in the following equations. x – 4 = 10         Solution 2x – 4 = 10         Solution 5x – 6 = 3x – 8         Solution           Solution          Solution 2(3x – 7) + 4 (3 x + 2) = 6 (5 x + 9 […]

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### Using Fibonacci to Easily Expand

April9

Now, you might well ask, how can we use Fibonacci to make our Algebra life easier. Well, here is a really good use which you can use in senior grades (note the pattern of coefficients in the expansion in red – same as the Fibonacci numbers to the left): answer to the 4th expansion will […]

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### So, what’s the use of learning all this Algebra stuff?

March21
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### Donald in Mathmagic Land – Pt II

March10

It is quite amazing the number of times that an innocent blog on this site results in further connections. For example, I have an interest in older books – not rare, but those that add to my meek understanding. While visiting a local library I picked up a book for sale which recounts the first […]

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### Why letters are better than boxes…

March9

This is quite a helpful note from purplemath.com on why we use letters rather than boxes when solving for variables in Algebra: See also this excellent video explanation for use of “x” when solving in Algebra.

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### x – Hide Your Eyes

February10

Have you ever looked up at the stars on a clear night and asked, “What is beyond the beyond the beyond?” Beyond the outer boundaries of space and time is the “unknown”. We use letters like x and y to indicate the unknown in mathematical terms. Perhaps the very best explanation of this is in […]

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#### Post Support

NCEA Level 2 Algebra Problem. Using the information given, the shaded area = 9, that is:
y(y-8) = 9 –> y.y – 8y – 9 =0
–> (y-9)(y+1) = 0, therefore y = 9 (can’t have a distance of – 1 for the other solution for y)
Using the top and bottom of the rectangle,
x = (y-8)(y+2) = (9-8)(9+2) = 11
but, the left side = (x-4) = 11-4 = 7, but rhs = y+? = 9+?, which is greater than the value of the opp. side??
[I think that the left had side was a mistake and should have read (x+4)?]