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Posts tagged with gradients

Video tutorials from Waldomaths

August6

Many students have found the video tutorials provided by Ron Barrow of Waldomaths quite helpful. For example, many of my Yr 8-10 students have greatly improved their understanding of Gradients of Straight Lines by watching this explanation;

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Gradients of Straight Lines revisited

July23

You are probably already familiar with the concept that the gradient or slope of a straight line is how much it rises over a given horizontal length – that is, the rise divided by the run. This video clip from Waldomaths is a very good explanation of gradients, and uses several examples: The gradient of […]

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Finding Gradients – Pt II

July25

Google Earth provides a practical tool to find gradients between two points . In this example, we are interested in the gradient between Mt Fuji and Yamanakako. The gradient is equal to the rise in elevation divided by the run (horizontal distance). In┬áthis portion of the cross-section we can calculate the gradient to = a […]

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How to find the gradient of a vertical line

June14

Many students struggle to figure out what the gradient of a vertical line is. Here is one explanation:

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Slope Dude!

June15

Not the best quality lesson on gradients but some students find it helps them remember the main concepts (from youtube and just over 2min):

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Post Support

NCEA Level 2 Algebra Problem. Using the information given, the shaded area = 9, that is:
y(y-8) = 9 –> y.y – 8y – 9 =0
–> (y-9)(y+1) = 0, therefore y = 9 (can’t have a distance of – 1 for the other solution for y)
Using the top and bottom of the rectangle,
x = (y-8)(y+2) = (9-8)(9+2) = 11
but, the left side = (x-4) = 11-4 = 7, but rhs = y+? = 9+?, which is greater than the value of the opp. side??
[I think that the left had side was a mistake and should have read (x+4)?]

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