## Welcome to H3 Maths

Blog Support for Growing Mathematicians

### Video tutorials from Waldomaths

August6

Many students have found the video tutorials provided by Ron Barrow of Waldomaths quite helpful. For example, many of my Yr 8-10 students have greatly improved their understanding of Gradients of Straight Lines by watching this explanation;

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### Gradients of Straight Lines revisited

July23

You are probably already familiar with the concept that the gradient or slope of a straight line is how much it rises over a given horizontal length – that is, the rise divided by the run. This video clip from Waldomaths is a very good explanation of gradients, and uses several examples: The gradient of […]

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### Finding Gradients – Pt II

July25

Google Earth provides a practical tool to find gradients between two points . In this example, we are interested in the gradient between Mt Fuji and Yamanakako. The gradient is equal to the rise in elevation divided by the run (horizontal distance). In this portion of the cross-section we can calculate the gradient to = a […]

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### How to find the gradient of a vertical line

June14

Many students struggle to figure out what the gradient of a vertical line is. Here is one explanation:

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### Slope Dude!

June15

Not the best quality lesson on gradients but some students find it helps them remember the main concepts (from youtube and just over 2min):

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#### Post Support

10 x 9 x 8 + (7 + 6) x 5 x 4 x (3 + 2) x 1 = 2020

NCEA Level 2 Algebra Problem. Using the information given, the shaded area = 9, that is:
y(y-8) = 9 –> y.y – 8y – 9 =0
–> (y-9)(y+1) = 0, therefore y = 9 (can’t have a distance of – 1 for the other solution for y)
Using the top and bottom of the rectangle,
x = (y-8)(y+2) = (9-8)(9+2) = 11
but, the left side = (x-4) = 11-4 = 7, but rhs = y+? = 9+?, which is greater than the value of the opp. side??
[I think that the left had side was a mistake and should have read (x+4)?]