## Welcome to H3 Maths

Blog Support for Growing Mathematicians

## Posts tagged with straight lines

### Video tutorials from Waldomaths

August6

Many students have found the video tutorials provided by Ron Barrow of Waldomaths quite helpful. For example, many of my Yr 8-10 students have greatly improved their understanding of Gradients of Straight Lines by watching this explanation;

by posted under Uncategorized | tagged under , , , ,  |  Comments Off on Video tutorials from Waldomaths

### Gradients of Straight Lines revisited

July23

You are probably already familiar with the concept that the gradient or slope of a straight line is how much it rises over a given horizontal length – that is, the rise divided by the run. This video clip from Waldomaths is a very good explanation of gradients, and uses several examples: The gradient of […]

by posted under Uncategorized | tagged under , ,  |  Comments Off on Gradients of Straight Lines revisited

### Finding Gradients – Pt 1

July20

If a road is steep we say that it has a “steep gradient”. Gradients are defined as the amount of increase in altitude (or rise) divided by the distance (or run) travelled. In the following diagram, you can find the gradient of the red line by taking any two points – here we are using […]

by posted under Uncategorized | tagged under , , , ,  |  Comments Off on Finding Gradients – Pt 1

#### Post Support

NCEA Level 2 Algebra Problem. Using the information given, the shaded area = 9, that is:
y(y-8) = 9 –> y.y – 8y – 9 =0
–> (y-9)(y+1) = 0, therefore y = 9 (can’t have a distance of – 1 for the other solution for y)
Using the top and bottom of the rectangle,
x = (y-8)(y+2) = (9-8)(9+2) = 11
but, the left side = (x-4) = 11-4 = 7, but rhs = y+? = 9+?, which is greater than the value of the opp. side??
[I think that the left had side was a mistake and should have read (x+4)?]