## Welcome to H3 Maths

Blog Support for Growing Mathematicians

## Archive for July, 2009

### Friday, July 31st

July28

Wow, we are having some problems posting new blogs today (must be an issue with the recent changes on this site). Homework for July 31st is Qu 4 and Qu 5 and Qu 6 page 243. Back to you soon with more information! If you are having problems solving simple equations then check the worked […]

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July26

Wow, we have just come to the end of the Trigonometry Section. Key thoughts were; Tri=3, so we are working with triangles – mainly right-angled triangles. Thanks to Pythagoras, we can solve right-angles triangles when just side measurements are given (hypotenuse squared = sum of the other two sides squared). Click here for a really […]

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#### Post Support

The graph on the left (Coronavirus) is for a time period of 30 days, while the one on the right (SARS) is for 8 months! Very poor graphical comparison and hardly relevant, unless it is attempting to downplay the seriousness of the coronavirus?

10 x 9 x 8 + (7 + 6) x 5 x 4 x (3 + 2) x 1 = 2020

NCEA Level 2 Algebra Problem. Using the information given, the shaded area = 9, that is:
y(y-8) = 9 –> y.y – 8y – 9 =0
–> (y-9)(y+1) = 0, therefore y = 9 (can’t have a distance of – 1 for the other solution for y)
Using the top and bottom of the rectangle,
x = (y-8)(y+2) = (9-8)(9+2) = 11
but, the left side = (x-4) = 11-4 = 7, but rhs = y+? = 9+?, which is greater than the value of the opp. side??
[I think that the left had side was a mistake and should have read (x+4)?]